An acute angle 0 is in a right triangle with cos 0=9/10. what is the value of sec 0

The value of sec O is  

Step-by-step explanation:

Given as for right angle triangle

cos O =

Now from Pythagoras theorem, for right angled triangle

H² = P² + B²

∵ cos O =  =

So Perpendicular² = Hypotenuse² - Base²

Or, Perpendicular² = 10² - 9²

Or, Perpendicular² = 100 - 81 = 19

∴   Perpendicular ( P ) =

∵ , Sec Ф =

So ,    Sec O =

Hence The value of sec O is      Answer

x = 10.1

step-by-step explanation:

all of the angles of a tirangle add up to 180º

180 - 65 = 115 (since we already know the value of one angle)

(2x + 7) + (8x + 7) = 115

(combins like terms) 10x + 14 = 115

(isolate the variable subtract 14 from both sides): 10x = 101

(find the variable divide both sides by 10): x = 101/10

x = 10.1

77

step-by-step explanation: