On a coordinate plane, a line goes through (negative 6, 8) and (2, 6). a point is at (negative 2, negative 4). what is the slope of the line that is parallel to the given line and passes through the given point? what is the equation, in point-slope form, of the line that is parallel to the given line and passes through the given point? what is the y-intercept of the line that is parallel to the given line and passes through the given point?

it will be a cylinder. with a diameter of 8 and 4 single pieces high

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752