Visitors to a carnival can buy an unlimited-ride pass for $50 or an entrance-only pass for $20. in one day, 282 passes were sold for a total of $10,680. the following system of equations models this scenario:

50x + 20y = 10,680
x + y = 282

how many unlimited-ride passes were sold?

The  unlimited-ride passes sold are equal to 168

Step-by-step explanation:

According to given scenario:

x = unlimited-ride passes

y = entrance-only pass

Given that:

50x + 20y = 10,680   eq1

x + y = 282   eq2

From eq2:

x = 282 - y

Putting value of x  in eq1:

50(282 - y) + 20y = 10,680

By simplifying:

14,100 - 50y + 20y = 10,680

14,100 - 30y = 10,680

30y = 14,100 - 10680

30y = 3,480

Dividing both sides by 30

y = 114

Now put value of y in eq2:

x + 114 = 282

x = 282 - 144

x = 168

So, the  unlimited-ride passes sold are equal to 168

i hope it will help you!

$30.32

step-by-step explanation:

65.00*.12=2.80

65.00-2.80=57.20

57.20*1.06=60.632

60.632/2=30.316