The jackson's have two pet dogs named beau and max. beau is 2 years older than max. the sum of their ages is 16 years. how old is beau? how old is max.

Step-by-step explanation:

Let the dogs' ages be represented by b and m.

  b + m = 16

  b - m = 2

Adding these equations gives ...

  2b = 18

  b = 9 . . . . . . divide by 2

  m = 7 . . . . . . 2 years younger than Beau

Beau is 9; Max is 7.

Once you realize the above solution is generic, you can write down the answer that (older) Beau is half the sum of the given numbers: (16 +2)/2 = 9. Then Max's age is easily found, or it can be computed as half the difference of the given numbers: (16 -2)/2 = 7.

she played for 18.75 hours.

step-by-step explanation:

if she played 2/4 of a hour on tuesday. and there is 60 minutes in an hour and 60 divided by 4 is 7.5. and she played 2/4 of an hour on thursday then again 60 divided by 4 is 7.5, you add 7.5+7.5=56.25. now you have to do 1/4 of an hour, it equals 3.75. now you have to add them all up. 3.75+7.5+7.5=18.75

i hope this and i hope you get it right. it took me a while to get this done for you. : )

75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.