Ahouse has 3 rectangular countertops. each countertop is 4 and 3/8 by 2 and 2/5 feet. how many square feet of tile is needed to cover all the countertops?

a. 8 3/20

b. 10 1/2

c. 24 9/20

d. 31 1/2

31\frac{1}{2}ft^2

Step-by-step explanation:

From the information given each of the three rectangular countertops has dimension 4\frac{3}{8} by  2\frac{2}{5} feet.

The area of a rectangular shapes is the product of the dimensions.

Each rectangular countertop has area;

4\frac{3}{8}\times 2\frac{2}{5}=\frac{35}{8}\times \frac{12}{5} =10\frac{1}{2}ft^2

Therefore the number of square feet tiles needed to cover all the countertops is D.

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4