Write an equation in point-slope form of the line that passes through point (3, 5) and has a slope of – 4.

-4x-y+17=0

Step-by-step explanation:

(y-y1)=m(x-x1)

(y-5)=-4(x-3)

y=-4x--12+5

y=-4x+17

-4x-y+17=0

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)