In parallelogram abcd, ad = 12 in, m∠c = 46º, m∠dba = 72º. find the area of abcd.

96.16 square in

Step-by-step explanation:

Given information: In parallelogram ABCD, AD = 12 in, m∠C = 46º, m∠DBA = 72º.

Opposite angles of a parallelogram are congruent.

According to the angle sum property, the sum of interior angles of a triangle is 180º.

Law of Sine:

Using Law of Sine we get

It means the base of parallelogram is 11.14 in.

Draw an altitude on AB from D.

In a right angle

In triangle ADE,

The height of the parallelogram is 8.632.

The area of parallelogram is

Therefore, the area of parallelogram is 96.16 square in.

You would have to multiply all of the numbers

Answer: v= lwhstep by step explanation: length x width x heightl = 12kmw = 6kmh = 6km12 x 6 = 7272 x 6 = 432therefore your answer would be c) 432 km^3