The prior probabilities for events a1, a2, and a3 are p(a1) = 0.20, p(a2) = 0.30, and p(a3) = 0.50. the conditional probabilities of event b given a1, a2, and a3 are p(b | a1) = 0.20, p(b | a2) = 0.40, and p(b | a3) = 0.30. (assume that a1, a2, and a3 are mutually exclusive events whose union is the entire sample space.) a. compute p(b

if you mean

then it's c. 8, -7/3

but if you mean

then it is

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

~

i don't see any

step-by-step explanation:

hello, sorry being so rude after all that fighting i found it kind of funny, so as me saying sorry here is an answer!

since the table showed her that   2km = 2000m.

to determine, how many km in 2000m, she would divide by 1000.

= 2000 / 1000 = 2 km.

similarly, for 8000m = 8000 / 1000 = 8 km

cheers to savings

~

your pal papaguy