The length of a rectangle is 4 cm greater than its width. if the area of the rectangle is 108 cm^2 what are the approximate dimensions of the rectangle?

Step-by-step explanation:

I think some values are incorrect. You could always ask your teacher.

Edit:

In case of approximate dimensions, the answer is bound to be in fraction form.

So,

The area of a rectangal is lxb.

If the length is 4cm more than the breadth, the required equation would be:

x(x+4).

So, area= lxb

108= x(x+4)

108= x^2 + 4x.

108÷4 = x^2

27 =x^2

x= √27

x+4=√27+4

for finding the midpoint of any given 2 pair of points simply add the respective x coordinates with other x coordinate and the y coordinate with other y coordinate and divide them by 2

in your question it will be :

(3+1)/2 for the x coordinate of mid point i.e 2

[8+(-4)]/2 for the y coordinate of midpoint i.e 2

so coordinates of mid point of points (3,8) and (1,-4) will be (2,2)