A true/false test has 8080 questions. suppose a passing grade is 5252 or more correct answers. test the claim that a student knows more than half of the answers and is not just guessing. assume the student gets 5252 answers correct out of 8080. use a significance level of 0.05. steps 1 and 2 of a hypothesis test procedure are given below. show step 3, finding the test statistic and the p-value and step 4, interpreting the results.

Let p be the proportion of the correct answers.

As per given , we have

, since the alternative hypothesis is right tailed , so the test is a one -tailed test.

If the student gets 52 answers correct out of 80.

i.e. the proportion of correct answers :

Test statistic :

P-value :   [ by using p-value table for z (right-tailed)]

Since the p-value(0.0037) is less than the significance level (0.05), so we reject the null hypothesis.

Results : We have enough evidence to support the claim that a student knows more than half of the answers and is not just guessing.

answer: 3.26019516

step-by-step explanation:

see explanation

step-by-step explanation:

a

(6r + 7) + (13 + 7r) ( remove brackets and collect like terms )

= 6r + 7 + 13 + 7r

= 13r + 20

b

remove brackets and collect like terms

13 - r - 1 + r

= 12 - r

c

remove brackets and collect like terms

= - 8 - r + 2r - 4

= - 12 + r

d

remove brackets and collect like terms

= 7r - - - 6r

[-   - = - - = - ]

= r -