Abox contains four red balls and eight black balls. two balls are randomly chosen from the box, and are not
replaced. let event b be choosing a black ball first and event r be choosing a red ball second.
what are the following probabilities?
p(b) =
p(rib) =
pbr) =
the probability that the first ball chosen is black and the second ball chosen is red is about percent.

it is c, trust i got your back lol

step-by-step explanation:

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

you are uyytr tyy

step-by-step explanation:

nswer: a   y-axis

step-by-step explanation: