Benjamin& associates, a real estate developer, recently builit 209 condominiums in mccall, idaho. the condos were either two-bedroom units or three-bedroom units if the total number of rooms in the entire complex is 530, how many two-bedroom units are there? how many three-bedroom units are there? there are a. two-bedroom units and b. three-bedroom units

2 bed room condos are 97 and 3 bed room condos are 112.

Step-by-step explanation:

Consider the provided information.

Benjamin& Associates, a real estate developer, recently builit 209 condominiums in McCall, Idaho.

Let number of 2 bed room units = x and 3 bed room units = y.

The total number of rooms in the entire complex is 530,

Substitute the value of y in above equation.

Now find the value of y as shown

Hence, 2 bed room condos are 97 and 3 bed room condos are 112.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

your answer would be 12