26) in a class of 30 students, approximately what is the probability that two of the students have their birthday on the same day (defined by same day and month) (assuming it’s not a leap year)? for example – students with birthday 3rd jan 1993 and 3rd jan 1994 would be a favorable event.

Answer is 0.696

Step-by-step explanation:

The sum number of sets possible for no two students to have the same birthday in a class of 30 is:

=30 * (30-1)/2

= 435.

Now, there are 365 days in a year. Therefore, the probability of students having a  birthday on a different date would be 364/365. Now there are a number of combination, to be exact 870 combinations.

So, the probability that no two students having the same birthday is:

(364/365)^435 = 0.303.

Now, the probability that two students would have their birthdays on the same equal date would be:

1-0.303 = 0.696 or 70%

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1

graph them on a graphing calculator, press 2nd trace. select intersect. hit enter until it says answer. ti 84 works best

step-by-step explanation: