Anew phone-answering system installed by a certain utility company is capable of handling ten calls every 10 minutes. prior to installing the new system, company analysts determined that the incoming calls to the system are poisson distributed with a mean equal to five every 10 minutes. if the analysts are correct about this incoming call distribution, what is the probability that in a 10-minute period more calls will arrive than the system can handle? based on this probability, comment on the adequacy of the new answering system. the probability that more calls will arrive than the system can handle is nothing.

0.0137

Step-by-step explanation:

Let X be the random variable that measures the number of incoming calls every ten minutes.

If the incoming calls to the system are Poisson distributed with a mean equal to 5 every 10 minutes, then the probability that there are k incoming calls in 10 minutes is

If the phone-answering system is capable of handling ten calls every 10 minutes, we want to find

P(X>10), or the equivalent 1 - P(X≤ 10).  

But

1 - P(X≤ 10)= 1 -(P(X=0)+P(X=1)+...+P(X=10)) =

So, the probability that in a 10-minute period more calls will arrive than the system can handle is 0.0137

trapezoid

step-by-step explanation:

first i plotted all my points on a grid graph

i made sure all of them were in the correct quadrant

then i saw it was a trapezoid or a quadrilateral

the anwser is d) 75°

step-by-step explanation: