1. lucy has a jewelry business. to make a certain necklace, she spends $4.52 on materials and $5.43 on labor. she then sells the necklace for $17.99. lucy’s profit on the necklace is equal to the sale price minus the cost of materials and labor. (a) how much profit does lucy earn when she sells a necklace? what fraction of the sale price of the necklace is profit? record your answer as a fraction using whole numbers. (b) what decimal of every dollar of the sale price of the necklace is profit? show your work. round your answer to the nearest hundredth. (c) lucy collected $215.88 selling necklaces at a craft fair. how many necklaces did lucy sell? how much profit did she earn? show your work.

the fraction of the sale price of this necklace would be (704/1599). To find the percent you would divide 7.04 by 15.99 to find the decimal would be 44%. 223.86/15.99=14 necklaces. 14(7.04)=$98.56 of profit.

Add the costs of material and labor together:

Subtract this value from how much Lucy sells a necklace for:

Lucy's profit from a necklace is $7.04.

Set up a fraction where the profit is the numerator, and the sale price is the denominator to get your ratio:

The ratio will be 704/1599.

b)

Divide the profit by the sale price:

Multiply the decimal by 100 to get your percentage:

Check the tenths value to round to the nearest percent:

0 < 5

44.03 ≈ 44

44% of the sale price is profit.

c)

Divide the total amount Lucy earned at the fair by the sale price of an individual necklace:

Lucy made 14 necklaces.

To find the total profit Lucy made from the fair, multiply the total amount of necklaces she made by the profit for each necklace:

Lucy's total profits were $98.56.

you can change values to find the answer just substitute

55/i dont know i do it for the points

step-by-step explanation:

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.