a rectangle has a length 6 m less than twice its width. when 2 m are added to the width, the resulting figure is a square with an area of 100 m2. find the dimensions
of the original rectangle.

A rectangle has a length 6m less than twice its width. when 5 m are added to the width, the resulting figure is a square with an area of 256m^2. find the distance of the original rectangle

width:: x

length:: 2x-6

New width:: x+5

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Equation:

(x+5)^2 =256 =16

16 is the original length

idk lol

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?