The probabilty that husband and wife will be a live is 30 years from now is 0.6 and 8.0 find the probabilty that in 30 years time a) both will be a live b) nether will be die c) at least one will be a live

a) 0.48

b) 0.08

c) 0.44

Step-by-step explanation:

The probabilty that husband and wife will be a live 30 years from now is 0.6 and 8.0.

If probability that husband will be alive 30 years from now is 0.6, then the probability that husband will not be alive 30 years from now is

1 - 0.6 = 0.4

If probability that wife will be alive 30 years from now is 0.8, then the probability that wife will not be alive 30 years from now is

1-0.8 = 0.2

a) probability that both will be a live will be

0.6 × 0.8 = 0.48

b) probability that nether will be alive

is

0.4 × 0.2=0.08

c) probability that at least one will be alive will be

Probability that husband would be alive and wife would die + probability that husband would die and wife would be alive

= 0.6×0.2 + 0.4 ×0.8

= 0.12+ 0.32 = 0.44

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

168

step-by-step explanation:

first off, we know that he drove 3.5 hours at a rate of 48 mph.

knowing that, we want to see how many miles he drove all-together.

in this case, we can just multiply 48 by 3.5.

48 * 3.5 = 168