An airplane has an airspeed of 430 miles per hour at a bearing angle of 135 degrees. the wind velocity is 35 miles per hours in the direction n30 degree e. find the resultant speed and the direction of the plane.

Step-by-step explanation:

an airplane has an airspeed of 430 miles per hour on a heading of 135 degrees. the wind velocity is 35 miles per hour in the direction N30degreesE. Find the resultant speed and direction of the plane.

Usually we say where the wind is from, but this seems to imply that the air is moving N 30 E . Again mathematicians do not get this stuff.

North speed = 430 cos 135 + 35 cos 30

= -273 mph or 273 south

East speed = 430 sin 135 + 35 sin 30

= 322 mph

total speed = sqrt(273^2+322^2) = 422 mph

angle of travel east of south = A

tan A = 322/273

A = 49.7

so actual direction over ground is

180 - 49.7 = 130.3 degrees East of North

step-by-step explanation:

let pq = qr = rs = x, and xz = y and zu = z.

if the horizontal lines are parallel, then corresponding segments are in proportion:

substitute:

therefore 3 = y = z.

xu = y + z → xu = 3 + 3 = 6