Write the equation of the line with slope -5 and passing through the point (-3, 4)
in point-slope form, y - yi = m(x – 21)
next, solve for y and write the equation of the line in slope-intercept form.

a) y -4  = -5 (x + 3)  is the equation of the line.

b )y = -5x  - 11  is the slope intercept form of the equation.

Step-by-step explanation:

The slope of the line  = -5  = m

The point is given as (-3,4)

Now, by POINT SLOPE FORMULA:

The equation of line is given as (y-y0) = m (x-x0)

Similarly, here the equation of line is given as

(y-4) = (-5)(x - (-3))

or, y -4  = -5 (x + 3)  is the equation of the line.

SLOPE INTERCEPT FORM  :  y  = mx  + C

So , here  y -4  = -5 (x + 3)  ⇒ y = -5x - 15 + 4

or, y = -5x  - 11  is the slope intercept form of the equation.

i dont know

step-by-step explanation:

the reason i dont know is because i have not taken this class and for that reason i haven't learned this stuff

hope i could