The speed of a title wave in meters/second is given by the square root of the product of the acceleration due to gravity on earth (9.8meters/second^2) and the depth of the ocean in meters. if the ocean is 500 meters deep what is the speed of the wave

70 m/s

Step-by-step explanation:

speed = √( g x depth ); where g = 9.8m/s²

given depth = 500m

equation becomes:

speed = √( g x depth )

= √( 9.8 x 500 )

= √( 9.8 x 500 )

=√4900

=70 m/s

70

Step-by-step explanation:

v=√gd

v=√9.8*500

v=√4900

v=70 ms^-1

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

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