Michael has $2.25 worth of dimes and quarters. he has twice as many dimes as
quarters. write a system of equations that could be used to determine the number of
dimes and the number of quarters that michael has. define the variables that you use
to write the system.

25x+10x=$2.25

25=quarters and 10=dimes x is what we will plug in (how many coins Michael has for each type of coin) and $2.25 is how much money he has all together

Step-by-step explanation:

i used a money calculator and this is what it came too.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

111

step-by-step explanation: