When two electrical resistors with resistancer1> 0 andr2> 0 are wired in parallelin a circuit, the combined resistancer, measured in ohms (ω), is given by1r=1r1+1r2(a) find∂r∂r1and∂r∂r2after solving forr(e. g.,r=. ) describe how an increase inr1withr2held constant affectsr. (willrincreaseor ) describe how a decrease inr2withr1held constant affectsr. (willrincreaseor decrease? )

a)

b) and c)

See explanation below

Step-by-step explanation:

a)

The combined resistance R is a function of the the two  

parallel  resistances

So

and we have

Similarly,

b)

If we divide both the numerator and denominator by in the expression for R, we get

hence, if we held constant and increase the fraction gets smaller and so does the denominator of R, as a consequence R gets larger.

When is very large, the denominator of R is close to 1, so R is close to

c)

By a symmetric reasoning, we see that R gets larger when holding constant and increases.

In this case, R gets closer to as grows.

i believe the answer is letter c) 8

step-by-step explanation:

d) 48

step-by-step explanation:

16,32,48,64,80,96,112,128,144,160,176,192,208,224,240,256,272,288,304,320,336