Devin purchased tickets to an air show for eight adults and two children the total cost was $140 and the cost of a child’s ticket was five dollars less than the cost of an adult ticket find the price of an adult ticket and a child’s ticket

The answer is: The adult ticket costs $15 and the child ticket costs $10.

Step-by-step explanation:

Let a = the dollar amount of adult tickets and c = the dollar amount for child tickets. The child ticket cost $5 less than the adult ticket. Then:

c = a - 5

The number of adult tickets times the adult cost plus the number of child tickets times the cost for child tickets is equal to the total dollar amount. Set up the equation:

8a + 2c = $140

Substitute:

8a + 2(a-5) = 140

8a + 2a - 10 = 140

10a = 150

a = 150 / 10 = 15, so the adult ticket is $15

Solve for c:

c = a - 5

c = 15 - 5 = 10, so the child ticket is $10

Proof:

8a + 2c = 140

8(15) + 2(10) = 140

120 + 20 = 140

140 =140

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40