In order to practice at home, tadeo purchased a basketball and a volleyball that cost a total of $67, not including tax. if the price of the basketball b is $4 more than twice the cost of the volleyball v. which system of linear equations could be used to determine the price of each ball?

a) b + v = 67; b = 2v - 4
b) b + v = 67; b = 2v + 4
c) b + v = 4; b = 2v - 67
d) b + v = 4; b = 2v + 67

B. b + v = 67; b = 2v + 4

Step-by-step explanation: since both the basketball and the volleyball cost 67, we can represent that as b + v = 67.

If you multiplied the cost of the volleyball by 2 and then added 4, you would get the cost of the basketball:

b = 2v + 4

Hope this was helpful! Let me know if you have any further questions. :)

i dont know

step-by-step explanation:

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl