To the nearest hundredth, what is the distance between point (-6, -1) and point (4, 3)?

Hi   , the answer is 10.7  

Step-by-step explanation:

the   distance between 2 points   is

the square  root (y2-y1)^2 + (x2-x1)^2

(-6,-1) -> (x1,y1)  

(4,3)  ->(x2,y2)  

so (3- - 1 ) ^2  + (4 - -6)^2 = 4^2 + 10^2 = 16+100 = 116

the square root for 116  =  10.7

thanks  

is there answer choices?