Mathematics, 10.11.2019 04:31 bricefitzpatrick0429
It is known that screws produced by a certain company will b defective with probability .01 independently of each other. the company sells the screws in packages of 25 and offers a money back guarantee that at most 1 of the 25 is defective, using poisson approximation for binomial distribution the probability that the company must replace a package is approximatelya).01b).1947c).7788d). 0264e).2211
Answers: 1
![P(x1)=1-(P(x\leq1))\\\\=1-[P(x=0)+P(x=1)]\\\\=1-[e^{-0.25}\cdot\frac{0.25^0}{0!}+e^{-0.25}\cdot\frac{0.25^1}{1!}]\\\\=1-0.9736=0.0264](/tpl/images/0367/6491/0aa78.png)
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