Arandom sample of 16 emergency reports was selected from the files of an ambulance service. the mean time( computed from these sample data) required for ambulances to reach their destinations was 13 minures, with a variance of 9. can we conclude at the 0.05 significance level that the mean is greater than 10 minutes? state and test the appropriate hypothesis.

We can conclude that the mean time is greater than 10 minutes.

Step-by-step explanation:

In this case we have to perform a hypothesis testing of the mean, with standard deviation of the population unknown.

The conclusion we have to demonstrate with evidence is that the mean is greater than 10 min, so the null and alternative hypothesis became:

The significance level is 0.05.

The test statistic is

For a sample size of n=13, the degrees of freedom are 13-1=12. We can look up in a t-table the P-value for a t=3.614 and df=12.

The P-value is 0.00178. As the P-value is less than the significance level, we can conclude that the effect is significant and the null hypothesis is rejected.

We can conclude that the mean time is greater than 10 minutes.

step-by-step explanation:

from the graph attached below:

domain of graph is the value of x for which the given function profit function p(x) is defined.

(a) the domain represents the number of years for which the outlet will earn a profit.

range of profit function defines the lowest to highest value of profit earned.

(b) the range of this function is (0 , 160 ). for this function, the range represents the outlet's profit earned.

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.