Suppose 15 quarts of a solution that is 35% antifreeze is mixed with 5 quarts of a solution that is 72% antifreeze. 1.how many quarts of antifreeze are in the resulting mixture? 2.what % of the resulting mixture is antifreeze?

1. 8.85 quarts

2. 44.25%

Step-by-step explanation:

In 15 quarts of a solution with percentage of antifreeze = 35%

Amount of antifreeze = 35% × 15

                                    = 0.35 × 15

                                    = 5.25 quarts

that solution is mixed with 5 quarts of a solution with percentage of antifreeze = 72%

Amount of antifreeze = 72% × 5

                                    = 0.72 × 5

                                    = 3.6 quarts

Total amount of mixture = 15 quarts + 5 quarts = 20 quarts

1. Now we will calculate the total amount of antifreeze in the resulting mixture.

= 5.25 + 3.6 = 8.85 quarts

2. The percentage of the resulting mixture is antifreeze

=

= 44.25%

1. total amount of antifreeze is 8.85 quarts

2. the percentage of antifreeze is 44.25%

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form