In the middle of a park there is a fenced off area in the shape of the fence says is a square. if the area of the fenced off portion is 225 yd.², what is the perimeter of the fence is?

Step-by-step explanation:

The formula for the area of a square is A = x^2, where x is the length of one side.  Equivalently, x^2 = A.

Here x^2 = 225 yd^2.  Taking the positive square root of both sides, x = 15 yd.

Thus, the perimeter of the square area enclosed by the fence is

P = 4(15 yd) = 60 yd

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

3 1/3 x 2 3/5 = 8 2/3

step-by-step explanation:

just multiply the first number by the second number to get your answer.