6. you have a coin collection of nickels and dimes containing 63 coins. if you have $5.05, how may of each coin
do you have?

n + d = 20n = 20 - d

0.05n + 0.10d = 1.35

0.05(20 - d) + 0.10n = 1.35

1 - 0.05d + 0.10d = 1.35

-0.05d + 0.10d = 1.35 - 1

0.05d = 0.35

d = 0.35/0.05

d = 7 < 7 dimes

n + d = 20

n + 7 = 20

n = 20 - 7

n = 13 <=== 13 nickels

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16

step-by-step explanation:

2 x 40 = 80

80/5

= 16

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.