Astudy on students drinking habits wants to determine the true average number of alcoholic drinks all fsu undergraduate students have in a one week period. we know from preliminary studies that the standard deviation is around 2. how many students should be sampled to be within 1 drink of population mean with 95% probability?

16

Step-by-step explanation:

Standard deviation is 2

Margin error for the problem is 1

Probability 95%, that means thet the siginficance level α is 1 – p

α = 1 – 0.95 = 0.05

margin of error (ME) can be defined as follows

ME = Z(α/2) * standard deviation/ √n

Where n is the sample size

Z(0.05/2) = Z(0.025)

Using a z table Z = 1.96

Now, replacing in the equation and find n

1 = 1.96 * 2/ √n

1 = 3.92 / √n

√n = 3.92

n = 3.92^2

n = 15.36 = 16

y > 1/3x

y < = -x + 4

hope this : )

60%