Suppose that a large family has 14 children, including two sets of identical triplets, three sets of identical twins, and two individual children. how many ways are there to seat these children in a row of chairs if the identical triplets or twins cannot be distinguished from one another?

15 batches are the most you can make

step-by-step explanation:

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step-by-step explanation:

yes

step-by-step explanation:

so of course you want to start by plugging the 5 in which goes to 7(5)+3(5)=50 because 7*5=35 and 3*5=15 and then add them together, then plug in the 5 to the other equation as well 9(5)+5=50 because 9*5= 45 and then add 5 and so yes they are equivalent.