Mathematics, 05.11.2019 06:31 dogerboy8380

Acontractor records the areas, in square feet, of several houses in a neighborhood to determine data about the neighborhood. which formula should be used to calculate the standard deviation?

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Answer from: katwilf1771

Step-by-step explanation:

Given that a contractor records the areas, in square feet, of several houses in a neighborhood to determine data about the neighborhood.

Let X1, X2,...Xn be the data set

We find mean of this by the formula sum/n

Mean = $\bar x =\frac{x_1+x_2+x_3+..+x_n}{n}$

Now variance is calculated as sum of squares of deviations of each entry from this mean.

Var(x) = $\frac{1}{n} \Sigma _{i=1} ^n(x_i-\bar x)^2$

Standard deviation = square root of variance

Thus first mean, then variance then sd deviation is calculated.

Answer from: sis212

The answer is B on edge

Step-by-step explanation:

The second answer is A: The data is a sample and is expected to be more dispersed from the mean.

Answer from: Quest

first option

a function is a relation in which an input is paired with exactly one output.

so, let's find the right answer.

in our first option, our inputs are january, february, and march. the outputs are 30, 28, and 25. each input has it's own output. this is correct!

our second option we know is incorrect, because ms. valverade has two outputs, dogs and cats. this is not a function.

our third option is incorrect as well. the yellow square has two ouputs, the square and the triangle.

lastly, in our fourth option, we see the number 7 two times with a different output. therefore, this is not a function.

remember: each input must be paired with only one output!

Me? ! with this question which relationship is a function?

Answer from: Quest

the system of inequity is

$y\leq -x+4$

$3y> x$

step-by-step explanation:

from the given graph it is noticed that we have two related lines. one is solid and another is dashed.

if a line passing through two points, then the equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

the solid line passing through the points (0,4) and (4,0).

$y-4=\frac{0-4}{4-0}(x-0)$

$y=-x+4$

the related equation of solid line is $y=-x+4$ .

similarly, find the related equation of dashed line. the dashed liune passing through the points (0,0) and (3,1).

$y-0=\frac{0-1}{3-0}(x-0)$

$3y=x$

the related equation of dashed line is $3y=x$

from the given graph it is noticed that the point (0,1) lies on the shaded region, therefore the point (0,1) must be satisfied by the related equations.

check the related equations by the point (0,1).

$1=-0+4$

$1=4$

this statement is true if the sign of inequality is < instead of equality. since it is an solid line therefore the sign of inequality will be $\leq$ . the required inequality is

$y\leq -x+4$

similarly, check the second related equation.

$3(1)=0$

it is a dashed line, so this statement is true if the sign of inequality is > . the required inequality is

$3y> x$

15 points write a system of inequalities to represent the shaded portion of the graph

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