Two tracking stations are on the equator 117 miles apart. a weather balloon is located on a bearing of upper n 43 degrees upper e from the western station and on a bearing of upper n 15 degrees upper e from the eastern station. how far is the balloon from the western station? round to the nearest mile.

Step-by-step explanation:

First, in the picture we have a drawing of this exercise. In this case, I will call A to the western station, and B the eastern station.

According to this, we have a triangle there, and we need to calculate the distance between C and A (Distance AC). This is the diagonal of that triangle. We only have the length of side AB which is 117 miles, and now, to get the side AC we need to use the sin law.

First, let's calculate the angle in B:

<ABC = 15 + 90 = 105°

This is the angle of that side of the triangle.

The angle in A:

<CAB = 90 - 43 = 47°

The angle in C:

<ACB = 180 - 47 - 105 = 28°

We have the three angles now.

Now the sin law is:

Sin< = opossite leg / hypotenuse

hypotenuse = opposite leg / sin<

Equaling both we have:

hypotenuse = AB / sin<ACB = AC/sin<ABC

AC = AB sin<ABC / sin<ACB

Solving for AC we have:

AC = 117sin105 / sin28

AC = 240.72 miles

answer: asdfghjkl,mnbv

step-by-step explanation:

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1