An employee suspected of having used an illegal drug is given two tests that operate independently of each other. test a has probability 0.9 of being positive if the illegal drug has been used. test b has probability 0.8 of being positive if the illegal drug has been used. what is the probability that neither test is positive if the illegal drug has been used?

0.02 or 2%

Step-by-step explanation:

The probability that test A is negative if the illegal drug has been used (P(A|N)) is 0.1 while the probability that test B is negative if the illegal drug has been used (P(B|N)) is 0.2.

Therefore, the probability that neither test is positive if the illegal drug has been used is:

There is a 0.02 or 2% probability that neither test is positive if the illegal drug has been used.

part 1 answer = 8

part 2 answer = 72

step-by-step explanation:

part 1 explanation = add all of the numbers, then divide by how many numbers you have. so, 200/25 = 8.

part 2 explanation = not gonna lie, this is hard to explain, so just google how to do it.

i think it would be 42cm