"suppose that you are a city planner who obtains a sample of 20 randomly selected members of a mid-sized town in order to determine the average amount of money that residents spend on transportation each month (such as fuel, vehicle repairs, and public transit). to 3 decimal places, what is the critical value for the 95% confidence interval

2.093

Step-by-step explanation:

As per give , we have

Sample size : n= 20

Degree of freedom : df= n-1=19

Significance level :

Since , the sample size is small (n<30) so we use t-test.

For confidence interval , we find two-tailed test value.

Using students's t-critical value table,

Critical t-value :

Thus, the critical value for the 95% confidence interval = 2.093

function 2 has a greater rate of change than function 1

function 2 has a greater y-intercept than function 1

step-by-step explanation:

step-by-step explanation:

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