Assume that trees are subjected to different levels of carbon dioxide atmosphere with 4% of the trees in a minimal growth condition at 340 parts per million (ppm), 11% at 460 ppm (slow growth), 47% at 540 ppm (moderate growth), and 38% at 650 ppm (rapid growth). what is the mean and standard deviation of the carbon dioxide atmosphere (in ppm) for these trees?

24.53

Step-by-step explanation:

We need to define our data, that is

 w -> x

0.04->340

0.11->460

0.47->540

0.38->650

We can obtain our mean,

To find the SE we need the Variance,

Make , then

t hope this

:

45.36 feet per second.

step-by-step explanation:

to find the most accurate determination for the number of feet per second tyrone traveled on his way to work let us convert miles to feet and minutes to seconds.

1 mile = 5280 feet.

1 minute = 60 seconds.

now we will divide 158400 by 3492 to find the most accurate determination for the number of feet per second tyrone traveled on his way to work.

therefore, tyrone traveled on his way to work at the rate of 45.36 feet per second.