The half-life of a certain radioactive substance is 65 days. there are 3.5 g present initially.
a. express the amount of substance remaining as a function of time t.
b. when will there be less than 1 g remaining?

r = 3.5 * .5^(t/65); around 117.5 days

Step-by-step explanation:

r = remaining substance

t = time in days

The half life is 65 day, meaning the .5 must be put to a power of t/65.

The initial substance was 3.5, which we must substitute in.

After using logarithms to solve our new equation, we are left with t=(about)117.5 days for there to be less than 1 gram of substance remaining.

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