Find the distance between
(-3,5) and (4,-2)

7√2 or approx. 9.89949

Step-by-step explanation:

distance between two points is

d=√(∆x^2+∆y^2)

where...

d is distance

∆x is change in x value

and ∆y is change in y value

In this problem ∆x=(-3)-4=(-7)

∆y=5-(-2)=7

plugging in those values gives us

d=√((-7)^2+7^2)

Solving this expression gives us

d=√(49+49)=√98

After simplifying the radical we are left with 7√2 or about 9.89949.

where is the diagram? shown below where? ?

step-by-step explanation: