In equilateral ∆abc, points m, p, and k belong to ab , bc , and ac respectively and am: mb = bp: pc = ck: ka = 1: 3. prove that ∆mpk is an equilateral triangle.

See explanation

Step-by-step explanation:

In equilateral ∆ABC,

Points M, P, and K belong to AB , BC , and AC respectively and

AM:MB = BP:PC = CK:KA = 1:3.

So,

Triangles AMK, BPM and CKP are all congruent by SAS postulate, so

If triangle MPK is equilateral triangle

false

step-by-step explanation:

rulers and compasses arent required in order to bisect an angle because when bisecting angles, you're making a "half circle" and considering in order to bisect an angle it wouldn't be straight, you wouldn't need either of the two