Asuspension bridge has two main towers of equal height. a visitor on a tour ship
approaching the bridge estimates that the angle of elevation to one of the towers
is 15°. after sailing 497 ft closer he estimates the angle of elevation to the same
tower to be 42° approximate the height of the tower.

The Height of the tower is 188.67 ft

Step-by-step explanation:

Given as :

The angle of elevation to tower = 15°

The distance travel closer to tower the elevation changes to 42° = 497 ft

Now, Let the of height of tower = h  ft

The distance between 42°  and  foot of tower = x  ft

So, The distance between 15° and  foot of tower =  ( x + 497 )  ft

So, From figure :

In Δ ABC

Tan 42° =

Or , Tan 42° =

Or,  0.900 =

∴ h = 0.900 x

Again :

In Δ ABD

Tan 15° =

Or , Tan 15° =

Or,  0.267 =

Or,  h = ( x + 497 ) × 0.267

So, from above two eq  :

     0.900 x =  ( x + 497 ) × 0.267  

Or, 0.900 x - 0.267 x =  497  × 0.267  

So, 0.633 x = 132.699

∴               x =

Or,            x = 209.63  ft

So, The height of tower = h = 0.900 × 209.63

Or,                                      h = 188.67 ft

Hence The Height of the tower is 188.67 ft    Answer

step-by-step explanation:

i am not sure sorry : c

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.