A3 digit number has tens digit 2 greater than the units digit and the hundreds digit 1 greater than the tens digit. the sum of the tens and hundreds digit is 3 times the units digit. what is the number?

875

Step-by-step explanation:

Let the units digit be 'x'.

So, according to the question,

tens digit = x + 2

hundreds digit = x + 3

also,

⇒ sum of tens and hundreds digit = 3 × the unit digit

⇒ (x + 2) + (x + 3) = 3x

⇒ x = 5.

so,

unit digit = 5

tens digit = 5 + 2 = 7

hundreds digit = 5 + 3 = 8

hence,

the number = (8 × 100) + (7 × 10) + 5

                    = 875.

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10