In a certain algebra 2 class of 29 students, 7 of them play basketball and 24 of them play baseball. there are 3 students who play neither sport. what is the probability that a student chosen randomly from the class plays both basketball and baseball?

Step-by-step explanation:

Let represent students playing basketball, represent students playing baseball.

Then, ,

Let be the total number of students. So, .

Now,

3 students play neither of the sport. So, students playing either of the two sports is given as:

∴

From the probability addition theorem,

Where, is the probability that a student chosen randomly from the class plays both basketball and baseball.

Plug in all the values and solve for . This gives,

Therefore, the probability that a student chosen randomly from the class plays both basketball and baseball is

answer: f = 32.2m

step-by-step explanation: that is the answer

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier