Asample of 14 joint specimens of a particular type gave a sample mean proportional limit stress of 8.48 mpa and a sample standard deviation of 0.79 mpa ("characterization of bearing strength factors in pegged timber connections," j. of structural engr., 1997: 326332). calculate and interpret a 95% lower confidence bound for the true average proportional limit stress of all such joints. what, if any, assumptions did you make about the distribution of proportional limit stress?

95% CI = ( 8.024 , 8.936 )

Step-by-step explanation:

Developing the exercise for a normal distribution then we have to calculate the degrees of freedom,

Where n, is our sample.

So in the table,

t = 2.1604

**Assumptions:

Population is normal distributed

i think the answer is .36

step-by-step explanation:

what i did was only 2.88 divided by 8

answer: c

because if you look at the chart you can see a pattern and compare it to the question he simplify out your

but i think the formula is f(x)=6x