1. determine whether -3 is a root of x3 + 3x2 + x + 1 = 0.
explain.

2. write a polynomial equation of least degree with
roots 3,-1, 2i, and -2i. how many times does the
graph of the related function intersect the x-axis?

1. The given equation does not have root at x = - 3.

2. (x - 3) (x + 1) (x² + 4) = 0

This curve will intersect twice the x-axis.

Step-by-step explanation:

1. If the right hand side of the equation  ......... (1) becomes same as the left hand side by putting x = - 3, then only we can conclude that x = - 3 is a root of the equation.

But in this case .

Therefore, x = - 3 is not a root of the above equation (1).

2. The equation of the polynomial with roots 3, -1, 2i, and -2i is

(x - 3) (x + 1) (x - 2i) (x + 2i) = 0

⇒ (x - 3) (x + 1) (x² + 4) = 0 (Answer)

Therefore, the graph of the above curve will intersect twice the x-axis in a real coordinate plane, at x = 3 and at x = -1. (Answer)

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine