What is the solution to the following equation? x^2+3x+4=0

a) x=1; x=-3
b) x=3; x=-1
c) x= -3+- square root of -7/ 2
d) x= 3+- square root of 25/2

x =−3±i√7/2

is the correc anwer

Option C

The solution of equation x^2+3x+4=0 is x= -3+- square root of -7/ 2

Solution:

Need to identify correct option for solution of the equation x^2 + 3x + 4 = 0.

Given equation is quadratic equation. We can find solution of this equation using quadratic formula.

According to quadratic formula for general equation solution of the equation is given by  

The given equation is So in our case, a = 1, b = 3 and c = 4

On applying quadratic formula we get

As i is square root of -1,

Hence correct option is C that is roots of quadratic equation

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°