Suppose an investment of $1,800 doubles in value every 7 years. how much is the investment worth after 42 years?
$151,200
$115,200
$21,600
$25,200

The investment worth after 42 years is $115200, so option 2 is correct

Solution:

Given, an investment of $1,800 doubles in value every 7 years. We have to find how much is the investment worth after 42 years from the given set of options.

Hence, the investment worth after 42 years is $115200, so option 2 is correct.

a = 11 : 4

b = 38

c = 1 for every 6

answer: it's d

step-by-step explanation: