triangle rst has vertices r(−2, 2), s(1, 1), and t(−1, −3). find the coordinates for the image of each vertex for the given rotation.

r(90°, 0) (triangle rst)

a.
r'(−2, −2), s'(−1, 1), and t'(3, −1)
b.
r'(−2, 2), s'(1, −2), and t'(3, 1)
c.
r'(2, 2), s'(−1, −1), and t'(1, −3)
d.
r'(−2, 2), s'(1, −1), and t'(3, 1)

A. and

Step-by-step explanation:

Given:

Vertices of triangle RST are and .

Rotation is 90° about the center O(0,0). The rotation is counter-clockwise as the angle of rotation is positive.

Now, the co-ordinate rule for 90° rotation counter-clockwise is given as: →

and values interchange their places with becoming negative when interchanged.

So, →

→

→

⇒ →

Therefore, the image of the vertices are and .

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10