the population of henderson city was 3,381,000 in 1994, and is growing at an annual rate 1.8%
5) if this growth continues, what will the approximate henderson city population be in the year 2000? between which years will the population of
henderson city double.

Step-by-step explanation:

   Given that the population grows every year at the same rate( 1.8% ), we can model the population similar to a compound Interest problem.

   From 1994, every subsequent year the new population is obtained by multiplying the previous years' population by = .

   So, the population in the year t can be given by

   Population in the year 2000 = =

Population in year 2000 = 3,762,979

   Let us assume population doubles by year .

≈

∴ By 2033, the population doubles.

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8