The product of two numbers is 32. find the sum of the two numbers s(x) as a function of one of the numbers, x. s(x) = find the positive numbers that minimize the sum and list them in increasing order: (smaller number) = ? (larger number) = ? let c be the smaller of the two numbers that minimize the sum. then c = ? s'(c) = ? and s"(c) = ?

Step-by-step explanation:

We are given the following information in the question:

The product of two numbers is 32.

Let the two numbers be x and y, then,

The sum of the two numbers = S(x)

First, we differentiate S(x) with respect to x, to get,

Equating the first derivative to zero, we get,

Solving, we get,

Again differentiation S(x), with respect to x, we get,

At,

Thus, minima occurs at x = for S(x).

If c be the smaller of the two numbers that minimize the sum, then,

idk

step-by-step explanation: i just don't

step-by-step explanation:

if you meant, "on the way from (3, 2) to (3, 14):

x does not change; y increases by 12.

ensure that you have copied down this problem correctly.   .